The equation $\sqrt {3 {x^2} + x + 5} = x - 3$ , where $x$ is real, has

  • [JEE MAIN 2014]
  • A

    no solution

  • B

    exactly one solution

  • C

    exactly two solution

  • D

    exactly four solution

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If $\alpha, \beta $ and $\gamma$ are the roots of equation ${x^3} - 3{x^2} + x + 5 = 0$ then $y = \sum {\alpha ^2} + \alpha \beta \gamma $ satisfies the equation

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